Operators
The Assignment
So now that we have the basics and we have an idea of how to work with Incrementing, Assigning, Adding, Subtracting, Multiplying, and Dividing, what follows is the code and the Assignment that you get to tackle.
Just take the info that you got and simply apply it.... You have got this!!!
The Code
using System;
namespace Parenthesis
{
class Program
{
static void Main(string[] args)
{
{
int i = 5;
int j = 10;
int m = 13;
int k;
// each of these lines below should be separate lines
// giving k increase i by 2
// giving k decrease j by i
// giving k divide i by j
// giving k increment k by 1
// giving k modulo m divided by i
// giving k increase k by k added to i
// giving k increase k by k divided by j
// giving k multiply k times k times k
// giving k increase k by i times j
}
}
}
}
Hints:
The language used to derive the desired output is actually pretty simple. The language is called "Expressions" and they are as follows.
Increase: add one variable to another, its special symbol is +
a = 13 and b = 5
example a + b = k
Result k = 18
Decrease: subtract one variable by another, its special symbol is -
a = 13 and b = 5
example a - b = k
Result k = 8
Increment: add one to a variable, its special character is ++
a = 13 and b = 5
Example k = k ++
Result k = 14
Explanation the ++ operator simply adds one to the numeric value of k every time is called upon
Modulo: is simply the remainder in any division problem and its special character is %
Special note: by using the modulo you are telling the computer to divide and only pay attention to the reminder
a = 13 b = 5
Example k = a % b
In this step above we are dividing 13 by 5 and then only paying attention to the remainder which is 3
Result k = 3
Assign: is an operator that makes a variable something else, its special character is =
a = 13 b = 5
Example k = a
In this step the value of a (which is 13) is assigned to k (which now becomes 13)
Result k = 13